5m^2-20m+10=15m-50

Solution for 5m^2-20m+10=15m-50 equation:

5m^2-20m+10=15m-50

We move all terms to the left:

5m^2-20m+10-(15m-50)=0

We get rid of parentheses

5m^2-20m-15m+50+10=0

We add all the numbers together, and all the variables

5m^2-35m+60=0

a = 5; b = -35; c = +60;
Δ = b2-4ac
Δ = -352-4·5·60
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-5}{2*5}=\frac{30}{10}
=3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+5}{2*5}=\frac{40}{10}
=4
$